![The binding energy of an imaginary iron ^5636Fe is (Given atomic mass of Fe is 55.9349 amu and that of hydrogen is 1.00783 amu. Mass of neutron is 1.00876 amu) The binding energy of an imaginary iron ^5636Fe is (Given atomic mass of Fe is 55.9349 amu and that of hydrogen is 1.00783 amu. Mass of neutron is 1.00876 amu)](https://dwes9vv9u0550.cloudfront.net/images/5745449/a2a43223-38f7-4083-9531-f26f2261c6d1.jpg)
The binding energy of an imaginary iron ^5636Fe is (Given atomic mass of Fe is 55.9349 amu and that of hydrogen is 1.00783 amu. Mass of neutron is 1.00876 amu)
![Given ({:(56),(26):}Fe)= 55. 934939u and m ({:(209),(83):}Bi)= 208. 980388u8 m ("proton") =1.007825u, m ("nutron")=1.008665u Then, BE per nucleon of Fe and Bi are respectively Given ({:(56),(26):}Fe)= 55. 934939u and m ({:(209),(83):}Bi)= 208. 980388u8 m ("proton") =1.007825u, m ("nutron")=1.008665u Then, BE per nucleon of Fe and Bi are respectively](https://d10lpgp6xz60nq.cloudfront.net/question-thumbnail/en_344756958.png)
Given ({:(56),(26):}Fe)= 55. 934939u and m ({:(209),(83):}Bi)= 208. 980388u8 m ("proton") =1.007825u, m ("nutron")=1.008665u Then, BE per nucleon of Fe and Bi are respectively
Find BE per nucleon of 56 Fe where m(56 Fe) = 55.936 u mn = 1.00727 u, mp = 1.007274 u - Sarthaks eConnect | Largest Online Education Community
![Given ({:(56),(26):}Fe)= 55. 934939u and m ({:(209),(83):}Bi)= 208. 980388u8 m ("proton") =1.007825u, m ("nutron")=1.008665u Then, BE per nucleon of Fe and Bi are respectively Given ({:(56),(26):}Fe)= 55. 934939u and m ({:(209),(83):}Bi)= 208. 980388u8 m ("proton") =1.007825u, m ("nutron")=1.008665u Then, BE per nucleon of Fe and Bi are respectively](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/644990943_web.png)